The diagonals of three faces of a rectangular parallelepiped that meet at a single corner measure √5 cm, √10 cm, and √13 cm. What is the volume of this parallelepiped?

एक आयताकार समान्तर चतुर्भुज (घनाभ) के तीन फलक, जो एक ही कोने पर मिलते हैं, उनके विकर्ण क्रमशः √5 सेमी, √10 सेमी और √13 सेमी हैं। इस समान्तर चतुर्भुज का आयतन क्या है?

This Question Asked In:
SSC, CGL MAINS 2026
  • A. 4 cm³
  • B. 5 cm³
  • C. 6 cm³
  • D. 8 cm³
Correct Answer :C - 6 cm³
Detailed Solution Video
Video Credit –Nikhil Sharma Maths
Detailed Text Solution

Let the edges of the rectangular parallelepiped be a, b and c.

The diagonals of the three faces meeting at one corner are:

√(a² + b²) = √5
√(b² + c²) = √10
√(c² + a²) = √13

Squaring:

a² + b² = 5
b² + c² = 10
c² + a² = 13

Adding all three equations:

2(a² + b² + c²) = 5 + 10 + 13
2(a² + b² + c²) = 28

a² + b² + c² = 14

Now subtract:

(a² + b² + c²) − (a² + b²) = 14 − 5
c² = 9 → c = 3

Similarly,

(a² + b² + c²) − (b² + c²) = 14 − 10
a² = 4 → a = 2

(a² + b² + c²) − (c² + a²) = 14 − 13
b² = 1 → b = 1

Volume = a × b × c
= 2 × 1 × 3
= 6 cm³

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