The diagonals of three faces of a rectangular parallelepiped that meet at a single corner measure √5 cm, √10 cm, and √13 cm. What is the volume of this parallelepiped?
एक आयताकार समान्तर चतुर्भुज (घनाभ) के तीन फलक, जो एक ही कोने पर मिलते हैं, उनके विकर्ण क्रमशः √5 सेमी, √10 सेमी और √13 सेमी हैं। इस समान्तर चतुर्भुज का आयतन क्या है?
This Question Asked In:
SSC, CGL MAINS 2026
Correct Answer :C - 6 cm³
Detailed Text Solution
Let the edges of the rectangular parallelepiped be a, b and c.
The diagonals of the three faces meeting at one corner are:
√(a² + b²) = √5
√(b² + c²) = √10
√(c² + a²) = √13
Squaring:
a² + b² = 5
b² + c² = 10
c² + a² = 13
Adding all three equations:
2(a² + b² + c²) = 5 + 10 + 13
2(a² + b² + c²) = 28
a² + b² + c² = 14
Now subtract:
(a² + b² + c²) − (a² + b²) = 14 − 5
c² = 9 → c = 3
Similarly,
(a² + b² + c²) − (b² + c²) = 14 − 10
a² = 4 → a = 2
(a² + b² + c²) − (c² + a²) = 14 − 13
b² = 1 → b = 1
Volume = a × b × c
= 2 × 1 × 3
= 6 cm³