Since ∠B = 90°, the orthocenter H of the triangle is at vertex B.

First find hypotenuse AC using Pythagoras theorem:
AC = √(6² + 8²)
= √(36 + 64)
= √100
= 10 cm.

In a right triangle, the midpoint of hypotenuse is the circumcenter.

Distance from right angle vertex (B) to midpoint of hypotenuse = half of hypotenuse = 10/2 = 5 cm.

Centroid G divides the line joining vertex B and midpoint of AC in ratio 2:1.

Therefore, distance GH = (1/3) × 5
= 5/3 cm.

Hence, the distance between centroid and orthocenter is 10/3 cm.